Import Question JSON

Current Question (ID: 7477)

Question:

$\text{The correct arrangement of the following electromagnetic spectrum in the increasing order of frequency is:}$

Options:

1. $\text{Cosmic rays} < \text{Amber light} < \text{Radiation of FM radio} < \text{X-rays} < \text{Radiation from microwave ovens}$
2. $\text{Radiation from FM radio} < \text{Radiation from microwave oven} < \text{Amber light} < \text{X-rays} < \text{Cosmic rays}$
3. $\text{Radiation from microwave ovens} < \text{Amber light} < \text{Radiation of FM radio} < \text{X-rays} < \text{Cosmic rays}$
4. $\text{Cosmic rays} < \text{X-rays} < \text{Radiation from microwave ovens} < \text{Amber light} < \text{Radiation of FM radio}$

Solution:

$\text{Hint: Spectrum of electromagnetic radiation}$ $\text{Explanation: The relation between frequency and wavelength is inverse.}$ $\text{The increasing order of frequency is as follows:}$ $\text{Radiation from FM radio} < \text{Radiation from microwave ovens} < \text{Amber light} < \text{X-rays} < \text{Cosmic rays}$ $\text{The increasing order of wavelength is as follows:}$ $\text{Cosmic rays} < \text{X-rays} < \text{Amber light} < \text{Radiation from microwave ovens} < \text{Radiation of FM radio}$ $\text{Since frequency and wavelength are inversely related (} \nu = \frac{c}{\lambda} \text{), the order of increasing frequency is the reverse of the order of increasing wavelength.}$ $\text{Therefore, the correct arrangement in increasing order of frequency is option 2.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}