Import Question JSON

Current Question (ID: 7512)

Question:

$\text{An absorption line of the lowest frequency in the transition of hydrogen spectra is:}$

Options:

1. $n=1 \text{ to } n=2$
2. $n=3 \text{ to } n=8$
3. $n=2 \text{ to } n=1$
4. $n=8 \text{ to } n=3$

Solution:

$\text{Hint: Gap in transition line should be low and transition should be from lower to higher.}$\n\n$\text{Explanation:}$\n\n$\text{As we go up in hydrogen spectrum, the energy differences decrease and wavelength increases.}$\n\n$\text{Absorption line in the spectra arises when energy is absorbed i.e., electron shifts from lower to higher orbit.}$\n\n$\text{Out of option 1 and 2, option 2 will have the lowest frequency as this falls in the Paschen series.}$\n\n$\text{For absorption, the transition must be from lower energy level to higher energy level, so options 3 and 4 are eliminated as they show transitions from higher to lower energy levels.}$\n\n$\text{Between options 1 and 2, option 2 (n=3 to n=8) represents a transition in the Paschen series which has a lower energy difference than the Lyman series transition in option 1 (n=1 to n=2).}$\n\n$\text{Since frequency is directly proportional to energy difference (}E = hf\text{), and the energy difference is smaller for the n=3 to n=8 transition, it will have the lowest frequency.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}