Import Question JSON

Current Question (ID: 7519)

Question:
$\text{Given below are two statements:}$\n\n$\text{Assertion (A): Bohr's orbits are also called stationary states.}$\n\n$\text{Reason (R): Electrons are stationary in an orbit.}$\n\n$\text{In light of the above statements, choose the correct answer from the options given below:}$
Options:
  • 1. $\text{Both (A) and (R) are true and (R) is the correct explanation of (A).}$
  • 2. $\text{Both (A) and (R) are true but (R) is not the correct explanation of (A).}$
  • 3. $\text{(A) is true but (R) is false.}$
  • 4. $\text{(A) is false but (R) is true.}$
Solution:
$\text{Hint: Bohr's orbits are also called stationary states.}$\n\n$\text{Explanation:}$\n\n$\text{The electron in the hydrogen atom can move around the nucleus in a circular path of fixed radius and energy. These paths are called orbits or stationary states.}$\n\n$\text{In Bohr's model, the term 'stationary states' refers to the fact that the electron can exist only in certain fixed energy levels or orbits without radiating energy. This is in contrast to classical electromagnetic theory, which predicted that an accelerating charged particle (like an electron orbiting a nucleus) should continuously emit radiation and lose energy.}$\n\n$\text{The electrons are not stationary in these orbits because they revolve around the nucleus with a specific velocity. The term 'stationary' in 'stationary states' refers to the stability of the energy of the orbit, not to the physical state of the electron itself.}$\n\n$\text{Therefore, assertion (A) is correct because Bohr's orbits are indeed called stationary states in quantum mechanics, as they represent specific energy states where the electron can exist without radiating energy.}$\n\n$\text{However, reason (R) is incorrect because electrons are not stationary in an orbit - they are constantly moving and revolving around the nucleus.}$\n\n$\text{Hence, (A) is true but (R) is false.}$

Import JSON File

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}