Import Question JSON

Current Question (ID: 7534)

Question:

$\text{Match the quantum numbers with the information provided by them:}$

Options:

1. $\text{A-2, B-4, C-1, D-3}$
2. $\text{A-1, B-2, C-3, D-4}$
3. $\text{A-1, B-4, C-3, D-2}$
4. $\text{A-4, B-1, C-3, D-2}$

Solution:

$\text{Hint: Orientation of the orbital is represented by m values.}$ $\text{Explanation:}$ $\text{A. Principal quantum number is the most important quantum number as it determines the size and to large extent the energy of the orbital.}$ $\text{B. Azimuthal quantum number determines the angular momentum of the electron and defines the three-dimensional shape of the orbital.}$ $\text{C. Magnetic quantum number gives information about the spatial orientation of orbitals with respect to a standard set of coordinate axes.}$ $\text{D. Spin quantum number arises from the spectral evidence that an electron in its motion around the nucleus in an orbit also rotates or spin about its own axis.}$ $\text{Therefore, the correct matching is:}$ $\text{A. Principal quantum number → 2. Energy and size of orbital}$ $\text{B. Azimuthal quantum number → 4. Shape of the orbital}$ $\text{C. Magnetic quantum number → 1. Orientation of the orbital}$ $\text{D. Spin quantum number → 3. Spin of electron}$ $\text{The correct answer is option 1: A-2, B-4, C-1, D-3}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}