Import Question JSON

Current Question (ID: 7537)

Question:

$\text{The correct set of four quantum numbers for the valence electron of a rubidium atom (Z = 37) is:}$

Options:

1. $5, 1, 1, +\frac{1}{2}$
2. $6, 0, 0, +\frac{1}{2}$
3. $5, 0, 0, +\frac{1}{2}$
4. $5, 1, 0, +\frac{1}{2}$

Solution:

$\text{Hint: Follow quantum number concept}$ $\text{For the given valence shell electron of Rubidium atom there will be following procedure to evaluate the quantum numbers as follows:}$ $\text{First, determine the electron configuration of Rubidium (Z = 37):}$ $\text{Rb: [Kr] 5s}^1$ $\text{The valence electron is in the 5s orbital.}$ $\text{Step-by-step determination of quantum numbers:}$ $\text{Principal quantum number: n = 5}$ $\text{(The electron is in the 5th shell)}$ $\text{Azimuthal quantum number: l = 0 (For s orbital)}$ $\text{(s orbital corresponds to l = 0)}$ $\text{Magnetic quantum number: m = 0 (As m = -l to +l)}$ $\text{(For l = 0, m can only be 0)}$ $\text{Spin quantum number: s = +}\frac{1}{2}$ $\text{(The single electron in 5s orbital has spin +1/2)}$ $\text{Therefore, the quantum numbers for the valence electron are: n = 5, l = 0, m = 0, s = +}\frac{1}{2}$ $\text{This corresponds to option 3.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}