Import Question JSON

Current Question (ID: 7538)

Question:

$\text{The quantum number not obtained from Schrödinger's wave equation is:}$

Options:

1. $n$
2. $l$
3. $m$
4. $s$

Solution:

$\text{Hint: We know that, to describe an electron completely we need four quantum numbers, they are, principal quantum number (n), Azimuthal quantum number(l), magnetic quantum number(m}_l\text{) and spin quantum number(s).}$ $\text{Schrödinger's wave equation gives only 3 quantum number, that is, n, l, and m.}$ $\text{The three quantum numbers obtained from Schrödinger's wave equation are:}$ $\text{1. Principal quantum number (n): Determines the energy level and size of the orbital}$ $\text{2. Azimuthal quantum number (l): Determines the shape of the orbital and angular momentum}$ $\text{3. Magnetic quantum number (m or m}_l\text{): Determines the orientation of the orbital in space}$ $\text{George Uhlenbeck and Samuel Goudsmit proposed the presence of the fourth quantum number known as the electron spin quantum number.}$ $\text{The spin quantum number (s or m}_s\text{) describes the intrinsic angular momentum (spin) of the electron and was not derived from Schrödinger's wave equation but was introduced to explain experimental observations such as the fine structure of atomic spectra and the Stern-Gerlach experiment.}$ $\text{Therefore, the quantum number not obtained from Schrödinger's wave equation is the spin quantum number (s).}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}