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Current Question (ID: 7545)

Question:

$\text{The number of electrons that can be fit into the orbital for which n = 3 and l = 1, is:}$

Options:

1. $2$
2. $6$
3. $10$
4. $14$

Solution:

$\text{Hint: An orbital can have a maximum 2 electron}$ $\text{Step 1: Read the statement carefully}$ $\text{An orbital can have a maximum 2 electron}$ $\text{Step 2: Identify the subshell}$ $\text{Given: n = 3 and l = 1}$ $\text{When n = 3 and l = 1, this corresponds to the 3p subshell.}$ $\text{Step 3: Determine the number of orbitals in the subshell}$ $\text{For l = 1 (p subshell), there are 3 orbitals (corresponding to m}_l = -1, 0, +1\text{)}$ $\text{Step 4: Calculate total electron capacity}$ $\text{Subshell 3p has three orbitals, one orbital can have two electrons hence 3 orbitals have 6 electrons.}$ $\text{Number of orbitals in 3p subshell = 3}$ $\text{Maximum electrons per orbital = 2}$ $\text{Total maximum electrons in 3p subshell = 3 × 2 = 6 electrons}$ $\text{Therefore, the correct answer is option 2.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}