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Current Question (ID: 7562)

Question:
$\text{The correct order of increasing energy of atomic orbital is:}$
Options:
  • 1. $\text{3s, 3p, 4s, 3d, 4p}$
  • 2. $\text{3s, 3p, 3d, 4s, 4p}$
  • 3. $\text{3s, 3p, 4s, 4p, 3d}$
  • 4. $\text{3s, 3p, 3d, 4p, 4s}$
Solution:
$\text{Hint: Use Bohr bury rule.}$\n\n$\text{Explanation:}$\n\n$\text{(i) (n + l) Rule = electron will enter having lesser value of (n+l)}$\n\n$\text{(ii) if (n+l) = same}$\n\n$\text{Electron will enter to the subshell having lesser value of n.}$\n\n$\text{orbitals}\quad\text{n+l}$\n\n$\text{3s = }\quad 3+0=3$\n\n$\text{3P= }\quad 3+1 = 4$\n\n$\text{4s = }\quad 4+0 =4$\n\n$\text{3d = }\quad 3+2 = 5$\n\n$\text{4p = }\quad 4+1 = 5$\n\n$= \text{3s} < \text{3p} < \text{4s} < \text{3d} < \text{4p}$\n\n$\text{So, the option 1 is the correct answer.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}