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Current Question (ID: 7564)

Question:

$\text{The group number and electronic configuration of element Z =114 is:}$

Options:

1. $\text{Halogen family, [Rn]5f}^{14}\text{6d}^{10}\text{7s}^2\text{7p}^5$
2. $\text{Carbon family, [Rn]5f}^{14}\text{6d}^{10}\text{7s}^2\text{7p}^2$
3. $\text{Oxygen family, [Rn]5f}^{14}\text{6d}^{10}\text{7s}^2\text{7p}^4$
4. $\text{Nitrogen family, [Rn]5f}^{14}\text{6d}^{10}\text{7s}^2\text{7p}^6$

Solution:

$\text{Hint: The valence shell electronic configuration of Z =114 is } \text{7s}^2 \text{ 7p}^2$\n\n$\text{Explanation:}$\n\n$\text{The element with atomic number, Z = 114 is flerovium (Fl). It is a super heavy artificial chemical element. In the periodic table of the elements, it is a transactinide element in the p-block.}$\n\n$\text{It is a member of the 7th period and is the heaviest known member of the carbon family.}$\n\n$\text{Electronic configuration for Z =114 is [Rn]}_{86}\text{5f}^{14} \text{ 6d}^{10} \text{ 7s}^2 \text{ 7p}^2$\n\n$\text{Thus, option 2 is the correct answer.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}