Import Question JSON

Current Question (ID: 7578)

Question:
$\text{The possible values of n, l, and m for the electron present in 3d would be}$ $\text{respectively:}$
Options:
  • 1. $n = 3, l = 1, m = -2, -1, 3, 1, 2$
  • 2. $n = 3, l = 3, m = -2, -1, 0, 1, 2$
  • 3. $n = 3, l = 2, m = -2, -1, 0, 1, 2$
  • 4. $n = 5, l = 2, m = -2, -1, 0, 1, 2$
Solution:
$\text{Hint: For 'n', value of 'l' = n-1 and value of 'm' = -l to +l}$\n\n$\text{Explanation:}$\n\n$\text{For the 3d orbital:}$\n\n$\text{Principal quantum number (n) = 3}$\n\n$\text{Azimuthal quantum number (l) = 2}$\n\n$\text{Magnetic quantum number (m) = -2, -1, 0, 1, 2}$\n\n$\text{Thus, option 3 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}