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Current Question (ID: 7619)

Question:
$\text{Elements with an electronic configuration}$ $1\text{s}^2 2\text{s}^2 2\text{p}^6 3\text{s}^2 3\text{p}^6 3\text{d}^{10} 4\text{s}^2 4\text{p}^6 4\text{d}^{10} 5\text{s}^2 5\text{p}^3$ $\text{belong to the group:}$
Options:
  • 1. $3^{\text{rd}}$
  • 2. $15^{\text{th}}$ (Correct)
  • 3. $17^{\text{th}}$
  • 4. $2^{\text{nd}}$
Solution:
$\text{HINT: The outer electronic configuration is}$ $5\text{s}^2 5\text{p}^3$\n\n$\text{Explanation:}$\n\n$\text{The outer electronic configuration is}$ $5\text{s}^2 5\text{p}^3$ $\text{which is resemble to p block elements general electronic configuration that is}$ $\text{ns}^{1-2}\text{np}^{1-6}$. $\text{Also the differentiating electron enters in p-sub shell, hence, it is a p-block element and for p-block element, the group is determined as the total number of electrons present in outer shell.}$\n\n$\text{The outermost shell contains 5 electrons and}$ $15^{\text{th}}$ $\text{group elements contains 5 electrons in its outermost shell. Hence it is belong to}$ $15^{\text{th}}$ $\text{group.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}