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Current Question (ID: 7629)

Question:
$\text{Element}$ $_{58}\text{Ce}$ $\text{belongs to:}$
Options:
  • 1. $\text{s-block elements}$
  • 2. $\text{p-block elements}$
  • 3. $\text{d-block elements}$
  • 4. $\text{f-block elements}$ (Correct)
Solution:
$\text{Explanation:}$\n\n$\text{Cerium's electron configuration is}$ $[\text{Xe}]4\text{f}^15\text{d}^16\text{s}^2$. $\text{It belongs to inner-transition metal series.}$\n\n$\text{Elements from atomic number 58 to 71 are f-block elements and are known as Lanthanoids or rare earths.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}