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Current Question (ID: 7646)

Question:
$\text{Increasing order of ionic radii and decreasing order of number of protons of the given isoelectronic species is:}$
Options:
  • 1. $\text{Ca}^{2+}, \text{K}^+, \text{Cl}^-, \text{S}^{2-}$ (Correct)
  • 2. $\text{Cl}^-, \text{Ca}^{2+}, \text{K}^+, \text{S}^{2-}$
  • 3. $\text{S}^{2-}, \text{Cl}^-, \text{Ca}^{2+}, \text{K}^+$
  • 4. $\text{None of the above}$
Solution:
$\text{HINT: In isoelectronic species anion size is greater than cation size.}$ $\text{Explanation:}$ $\text{Isoelectronic species are those species which have equal number of electrons. In isoelectronic species as positive charge on cation increases the radius of cation also decreases. In case of anion, as negative charge on anion increases the size of anion also increases.}$ $\text{The increasing order of the ionic radii and decreasing order of number of protons of the given isoelectronic species is as follows:}$ $\text{Ca}^{2+} < \text{K}^+ < \text{Cl}^- < \text{S}^{2-}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}