Import Question JSON

Current Question (ID: 7658)

Question:

$\text{Boron has lesser ionization enthalpy than Beryllium, because:}$

Options:

1. $\text{It is easier to remove electrons from p - a subshell than a filled s - subshell.}$ (Correct)
2. $\text{The s-electron can be removed easier than the p-electron.}$
3. $\text{Ionization enthalpy decreases with an increase in atomic number.}$
4. $\text{Ionization enthalpy increases along the period.}$

Solution:

$\text{HINT- Ionisation energy increases along a period.}$\n\n$\text{During the process of ionization, the electron to be removed from beryllium atom is a 2s-electron, whereas the electron to be removed from boron atom is a 2p-electron.}$\n\n$\text{Now, 2s-electrons are more strongly attached to the nucleus than 2p-electrons. Therefore, more energy is required to remove a 2s-electron of beryllium than that required to remove a 2p-electron of boron.}$\n\n$\text{Hence beryllium has higher } \Delta_i H \text{ than boron.}$\n\n$\text{This shows that it is easier to remove electrons from p-subshell than from a filled s-subshell, making option 1 correct. The 2p electron in boron is at a higher energy level and less tightly bound compared to the 2s electron in beryllium, despite the general trend of increasing ionization energy across a period.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}