Import Question JSON

Current Question (ID: 7686)

Question:
$\text{An element with higher negative electron gain enthalpy in the given pair is:}\n\text{(i) O or F (ii) F or Cl}$
Options:
  • 1. $\text{O, Cl}$
  • 2. $\text{F, F}$
  • 3. $\text{O, F}$
  • 4. $\text{F, Cl}$ (Correct)
Solution:
$\text{HINT: Electron affinity of a 3rd-period element is higher, and it increases from left to right in the period.}$\n\n$\text{Explanation:}$\n\n$\text{(i) O and F are present in the same period of the periodic table.}$\n\n$\text{Fluorine is a more electronegative element than oxygen atom hence, it stabilized the extra electron more easily than oxygen. Hence, fluorine has higher negative electron gain enthalpy than oxygen.}$\n\n$\text{(ii) The value of the electron gain enthalpy of Cl is more negative than that of F. This is because the atomic size of F is smaller than that of Cl. In F, the electron will be added to quantum level n = 2, but in Cl, the electron is added to quantum level n = 3. Therefore, there are less electron-electron repulsions in Cl and an additional electron can be accommodated easily.}$\n\n$\text{Hence, the electron gain enthalpy of Cl is more negative than that of F.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}