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Current Question (ID: 7699)

Question:
$\text{Allred Rochow's scale is related to:}$
Options:
  • 1. $\text{Electronegativity, radius, and Z}^*$ (Correct)
  • 2. $\text{Resonance energy of the molecule, ionisation potential and electron affinity.}$
  • 3. $\text{Bond Polarity, diagonal relationship and periodicity.}$
  • 4. $\text{None of the above.}$
Solution:
$\text{HINT: Electronegativity} = 0.744 + \frac{0.365Z^*}{r^2}$\n\n$\text{Explanation:}$\n\n$\text{Allred-Rochow Electronegativity is a measure that determines the values of the electrostatic force exerted by the effective nuclear charge on the valence electrons. The value of the effective nuclear charges is estimated from Slater's rules. The higher charge, the more likely it will attract electrons.}$\n\n$\text{According to Allred Rochow's scale :}$\n\n$\text{Electronegativity} = 0.744 + \frac{0.365Z^*}{r^2}$\n\n$\text{where, Z}^* \text{ is the effective nuclear charge and 'r' is the radius.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}