Import Question JSON

Current Question (ID: 7836)

Question:

$\text{Those in a group that falls under the law of triads include:}$

Options:

1. $\text{Cl, Br, I}$ (Correct)
2. $\text{C, N, O}$
3. $\text{Na, K, Rb}$
4. $\text{H, O, N}$

Solution:

$\text{HINT: Arithmetic mean of the atomic weight of the first and third element in a triad would be approximately equal to the atomic weight of the second element in that triad.}$ $\text{Explanation:}$ $\text{Here, Br atomic weight is the arithmetic mean of the atomic masses of the Cl and I. The calculation is as follows:}$ $\text{Br} = \frac{\text{At. wt. of Cl} + \text{At. wt. of I}_2}{2}$ $= \frac{35.5 + 127.2}{2}$ $= 81.25,$ $\text{Br} = 80, \text{ which is close to } 81.25$ $\text{Only four triads were mentioned by Dobereiner} = (\text{Li,Na,K}), (\text{Ca,Sr,Ba}), (\text{Cl,Br,I}), (\text{S,Se,Te}).$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}