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Current Question (ID: 7843)

Question:
$\text{The outermost electronic configuration of the last element of the p-block in the 6th period is represented by:}$
Options:
  • 1. $7\text{s}^2 7\text{p}^6$
  • 2. $5\text{f}^{14} 6\text{d}^{10} 7\text{s}^2 7\text{p}^0$
  • 3. $4\text{f}^{14} 5\text{d}^{10} 6\text{s}^2 6\text{p}^6$ (Correct)
  • 4. $4\text{f}^{14} 5\text{d}^{10} 6\text{s}^2 6\text{p}^4$
Solution:
$\text{HINT: The last element in 6th period is Radon (Rn)}$ $\text{Explanation:}$ $\text{Each period starts with the filling of electrons in a new principal energy shell. Therefore, the 6th period starts with the filling of the 6s-orbital and ends when 6p-orbitals are completely filled.}$ $\text{In between 4f and 5d-orbitals are filled in accordance with the Aufbau principle. Thus, the outermost electronic configuration of the last element of the p-block in the 6th period is } 6\text{s}^2 4\text{f}^{14} 5\text{d}^{10} 6\text{p}^6 \text{ or } 4\text{f}^{14} 5\text{d}^{10} 6\text{s}^2 6\text{p}^6.$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}