Import Question JSON

Current Question (ID: 7865)

Question:

$\text{The maximum number of elements that can be accommodated in the sixth period are:}$

Options:

1. $8$
2. $18$
3. $32$ (Correct)
4. $16$

Solution:

$\text{HINT- In the 6th period, electrons can be filled in only 6s, 4f, 5d, and 6p subshells.}$\n\n$\text{Explanation:}$\n\n$\text{STEP 1- 6s has one orbital, 4f has seven orbitals, 5d has five orbitals, and 6p has three orbitals.}$\n\n$\text{Therefore, there are a total of sixteen (1 + 7 + 5 + 3 = 16) orbitals available.}$\n\n$\text{STEP 2- According to Pauli's exclusion principle, each orbital can accommodate a maximum of 2 electrons.}$\n\n$\text{Thus, 16 orbitals can accommodate a maximum of 32 electrons.}$\n\n$\text{Hence, the sixth period of the periodic table should have 32 elements.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}