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Current Question (ID: 7873)

Question:

$\text{The position of elements with an outer electronic configuration as}$ $(\text{n} - 2) \text{f}^7 (\text{n} - 1) \text{d}^1 \text{ns}^2$, $\text{n} = 6$ $\text{:}$

Options:

1. $6^{\text{th}} \text{period and } 10^{\text{th}} \text{group.}$
2. $7^{\text{th}} \text{period and } 3^{\text{rd}} \text{group.}$
3. $6^{\text{th}} \text{period and } 3^{\text{rd}} \text{group.}$ (Correct)
4. $7^{\text{th}} \text{period and } 9^{\text{th}} \text{group.}$

Solution:

$\text{HINT: The highest principal quantum number indicates the period number and all actinoids are from the 3rd group.}$\n\n$\text{Explanation:}$\n\n$\text{Since n = 6, the element is present in the 6th period. It is an f –block element as the last electron occupies the f –orbital. It belongs to group 3 of the periodic table since all f-block elements belong to group 3.}$\n\n$\text{Its atomic number is 54 + 7 + 2 + 1 = 64. Hence, the element is Gadolinium.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}