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Current Question (ID: 7882)

Question:

$\text{The statement that is incorrect for the periodic classification of elements is:}$

Options:

1. $\text{The properties of elements are a periodic function of their atomic number.}$
2. $\text{Non-metallic elements are lesser in number than metallic elements.}$
3. $\text{The first ionization energies of elements along a period do not vary in a regular manner with an increase in atomic number.}$
4. $\text{For transition elements, the d-subshells are filled with electrons monotonically with an increase in atomic number.}$ (Correct)

Solution:

$\text{HINT: Filling of electrons in d-orbitals is not monotonic.}$ $\text{Explanation:}$ $\text{In Cr 3d}^5\text{4s}^1 \text{ and in Cu 3d}^{10}\text{4s}^1$ $\text{The electronic configuration of Mn and Cr are 3d}^5\text{4s}^2 \text{ and 3d}^6\text{4s}^1 \text{ and in Cu 3d}^{10}\text{4s}^1 \text{ respectively.}$ $\text{Both have the same number of d electrons.}$ $\text{Hence option 4 (For transition elements, the d-electrons are filled monotonically with an increase in atomic number) is false as d-electrons do not fill monotonically with the increase in atomic number.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}