Import Question JSON

Current Question (ID: 7887)

Question:

$\text{The correct statement about the radius of a species is:}$

Options:

1. $\text{Radius increases during cation and anion formation.}$
2. $\text{Radius increases during anion formation and decreases during cation formation.}$ (Correct)
3. $\text{Radius decreases in cation as well as anion.}$
4. $\text{Radius decreases during anion formation and increases during cation formation.}$

Solution:

$\text{HINT: An increase in the number of electrons will cause more repulsion and size will increase.}$ $\text{Explanation:}$ $\text{(a)}$ $\text{When an atom gains an electron, its size increases. When an electron is added, the number of electrons goes up by one. This results in an increase in repulsion among the electrons. However, the number of protons remains the same.}$ $\text{As a result, the effective nuclear charge of the atom decreases, and the radius of the atom increases.}$ $\text{(b)}$ $\text{When an atom loses an electron, the number of electrons decreases by one while the nuclear charge remains the same. Therefore, the interelectronic repulsions in the atom decrease.}$ $\text{As a result, the effective nuclear charge increases. Hence, the radius of the atom decreases.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}