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Current Question (ID: 7890)

Question:
$\text{Among the following species, the smallest ion is:}$
Options:
  • 1. $\text{Na}^+$ (Correct)
  • 2. $\text{F}^-$
  • 3. $\text{O}^{2-}$
  • 4. $\text{N}^{3-}$
Solution:
$\text{HINT: In isoelectronic species cation size is smaller than anion size.}$ $\text{Explanation:}$ $\text{As positive oxidation state in ion increases the radius of ion decreases. In case of anion if negative oxidation state of anion increases the size of anion also increases. The order of ionic radius is as follows:}$ $\text{N}^{3-} > \text{O}^{2-} > \text{F}^- > \text{Na}^+$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}