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Current Question (ID: 7899)

Question:

$\text{The size of isoelectronic species: F}^-, \text{Ne and Na}^+, \text{ is affected by:}$

Options:

1. $\text{Nuclear charge (Z)}$ (Correct)
2. $\text{Valence principal quantum number (n)}$
3. $\text{Electron-electron interaction in the outer orbitals}$
4. $\text{None of the above factors because their size is the same}$

Solution:

$\text{HINT: The size of an atom or ion depends on the effective nuclear charge.}$ $\text{Explanation:}$ $\text{The size of an isoelectronic species increases with a decrease in the nuclear charge (Z).}$ $\text{For example, the order of the increasing nuclear charge of F}^-, \text{Ne, and Na}^+ \text{ is as follows:}$ $\text{F}^- < \text{Ne} < \text{Na}^+$ $\text{Z} = 9 \quad 10 \quad 11$ $\text{Therefore, the order of the increasing size of F}^-, \text{Ne and Ne and Na}^+ \text{ is as follows:}$ $\text{Na}^+ < \text{Ne} < \text{F}^-$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}