Import Question JSON

Current Question (ID: 7946)

Question:

$\text{The electronegativity of the following elements increases in the order of:}$

Options:

1. $\text{S} < \text{P} < \text{N} < \text{O}$
2. $\text{P} < \text{S} < \text{N} < \text{O}$ (Correct)
3. $\text{N} < \text{O} < \text{P} < \text{S}$
4. $\text{N} < \text{P} < \text{S} < \text{O}$

Solution:

$\text{HINT: Left to right electronegativity increases.}$\n\n$\text{Explanation:}$\n\n$\text{Electronegativity, symbolized as χ, is the tendency for an atom of a given chemical element to attract shared electrons when forming a chemical bond.}$\n\n$\text{From top to bottom down a group, electronegativity decreases. This is because atomic number increases down a group, and thus there is an increased distance between the valence electrons and nucleus, or a greater atomic radius.}$\n\n$\text{Electronegativity increases across a period because the number of charges on the nucleus increases that attracts the bonding pair of electrons more strongly.}$\n\n$\text{As per trend, electronegativity increases in a period and decreases down the group.}$\n\n$\text{The correct order is as follows:}$\n\n$\text{P} < \text{S} < \text{N} < \text{O}$\n\n$2.19 < 2.58 < 3 < 3.5$\n\n$\text{So, option 2 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}