Import Question JSON

Current Question (ID: 7950)

Question:

$\text{Percentage ionic character, if electronegativity value of X=2.1 \& Y=3.0, is :-}$

Options:

1. $20$
2. $30$
3. $17$ (Correct)
4. $23$

Solution:

$\text{HINT: Ionic percentage formula} = 16 \times (\Delta E) + 3.5(\Delta E)^2$\n\n$\text{Explanation:}$\n\n$\text{Calculate the ionic percentage of XY is as follows:}$\n\n$\text{Ionic percentage of XY} = 16 \times (\Delta E) + 3.5(\Delta E)^2 \text{ where } \Delta E \text{ is the electronegativity difference.}$\n\n$= 16 \times 0.9 + 3.5[0.9]^2$\n\n$\text{Ionic percentage of XY} = 17.2\% \text{ (ionic)}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}