Import Question JSON

Current Question (ID: 8036)

Question:

A molecule having the smallest bond angle among the following is :

Options:

1. $\text{SO}_2$
2. $\text{H}_2\text{O}$
3. $\text{H}_2\text{S}$
4. $\text{NH}_3$

Solution:

\text{Bond angle totally depends on hybridization.} \text{Explanation:} \text{Molecule: SO}_2, \text{Hybridization: sp}^2, \text{Repulsion: lp-bp, bp-bp, Bond angle: } 119° \text{Molecule: H}_2\text{O}, \text{Hybridization: sp}^3, \text{Repulsion: lp-lp, bp-bp, lp-bp, Bond angle: } 104.5° \text{Molecule: H}_2\text{S}, \text{Hybridization: No hybridization, Bond angle: } 92° \text{Molecule: NH}_3, \text{Hybridization: sp}^3, \text{Repulsion: lp-bp, bp-bp, Bond angle: } 107° \text{Among the given molecules, H}_2\text{S} \text{ has the smallest bond angle of } 92°. \text{ This is because for elements from period 3 and beyond (like S in H}_2\text{S}\text{), the bond angles tend to be closer to } 90° \text{ due to negligible hybridization and the involvement of p-orbitals in bonding. This phenomenon is known as Drago's Rule. The lone pair repulsion in H}_2\text{S} \text{ is also higher than in H}_2\text{O} \text{ due to the larger size of the sulfur atom, which pushes the bonding pairs closer.} \text{Hence, option third is the answer.}

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}