Import Question JSON

Current Question (ID: 8088)

Question:

$\text{Combination of atoms A and B that forms an anti-bonding molecular orbital is:}$

Options:

1. $\frac{\Psi_A^2}{\Psi_B^2}$
2. $\Psi_A^2 \times \Psi_B^2$
3. $\Psi_A + \Psi_B$
4. $\Psi_A - \Psi_B$

Solution:

$\text{HINT: Molecular orbitals may be described by the linear combination of atomic orbitals.}$ $\text{Explanation:}$ $\text{The two-electron waves of bonding atoms cancel out each other due to destructive interference. So, the electron density is located away from the space between the nuclei. Hence, repulsion between the nuclei is high.}$ $\text{Hence, electrons in antibonding molecular orbital tend to destabilize the molecule. The energy of the antibonding molecular orbital remains high.}$ $\text{However, the total energy of two molecular orbitals remains the same as that of two original atomic orbitals.}$ $\text{The combination of atoms A and B forms an anti-bonding molecular orbital is:}$ $\sigma^* = \Psi_A - \Psi_B$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}