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Current Question (ID: 8092)

Question:

$\text{N}_2 \text{ and } \text{O}_2 \text{ are converted to monocations } \text{N}_2^+ \text{ and } \text{O}_2^+ \text{ respectively. Which of the following is incorrect?}$

Options:

1. $\text{In } \text{N}_2^+, \text{ the } \text{N} - \text{N} \text{ bond weakens.}$
2. $\text{In } \text{O}_2^+, \text{ the } \text{O} - \text{O} \text{ bond order increases.}$
3. $\text{In } \text{O}_2^+, \text{ the paramagnetism decreases.}$
4. $\text{N}_2^+ \text{ becomes diamagnetic.}$

Solution:

$\text{HINT: Bond strength } \propto \text{ Bond order } \propto \frac{1}{\text{Bond length}}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{1.) Electronic configuration of } \text{O}_2 \text{ (16 electrons)} = \sigma_{1s}^2, \sigma_{1s}^{*2}, \sigma_{2s}^2, \sigma_{2s}^{*2}, \sigma_{2p_z}^2, \pi_{2p_x}^2 \approx \pi_{2p_y}^2, \pi_{2p_x}^{*1} \approx \pi_{2p_y}^{*1}$ $\text{Bond order} = \frac{1}{2}(N_b - N_a) = \frac{1}{2}(10 - 6) = 2$ $\text{2.) Electronic configuration of } \text{O}_2^+ \text{ (15 electrons)} = \sigma_{1s}^2, \sigma_{1s}^{*2}, \sigma_{2s}^2, \sigma_{2s}^{*2}, \sigma_{2p_z}^2, \pi_{2p_x}^2 \approx \pi_{2p_y}^2, \pi_{2p_x}^{*1} \approx \pi_{2p_y}^{*0}$ $\text{Bond order} = \frac{1}{2}(N_b - N_a) = \frac{1}{2}(10 - 5) = 2.5$ $\text{3.) Electronic configuration of } \text{N}_2 \text{ (14 electrons)} = \sigma_{1s}^2, \sigma_{1s}^{*2}, \sigma_{2s}^2, \sigma_{2s}^{*2}, \pi_{2p_x}^2 \approx \pi_{2p_y}^2, \sigma_{2p_z}^2$ $\text{Bond order} = \frac{1}{2}(N_b - N_a) = \frac{1}{2}(10 - 4) = 3$ $\text{4.) Electronic configuration of } \text{N}_2^+ \text{ (13 electrons)} = \sigma_{1s}^2, \sigma_{1s}^{*2}, \sigma_{2s}^2, \sigma_{2s}^{*2}, \pi_{2p_x}^2 \approx \pi_{2p_y}^2, \sigma_{2p_z}^1$ $\text{Bond order} = \frac{1}{2}(N_b - N_a) = \frac{1}{2}(9 - 4) = 2.5$ $\text{STEP 2:}$ $\text{When } \text{N}_2 \text{ is converted to } \text{N}_2^+ \text{ then bond order decreases from 3 to 2.5 while } \text{O}_2 \text{ is converted into } \text{O}_2^+ \text{ then bond order increases from 2 to 2.5.}$ $\text{O}_2^+, \text{N}_2^+ \text{ \& } \text{O}_2 \text{ are paramagnetic while } \text{N}_2 \text{ is diamagnetic.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}