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Current Question (ID: 8101)

Question:

$\text{Compound that does not exhibit hydrogen bonding is-}$

Options:

1. $\text{CH}_3\text{CH}_2\text{OH}$
2. $\text{H}_3\text{C}—\text{C}(=\text{O})—\text{OH}$
3. $\text{H}_3\text{C}—\text{C}(=\text{O})—\text{CH}_3$
4. $\text{H}_3\text{C}—\text{C}(=\text{O})—\text{NH}_2$

Solution:

$\text{HINT: Ketones does not exhibit H-Bonding.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{There are two requirements for hydrogen bonding.}$ $\text{1. Molecules has a hydrogen attached to a highly electronegative atom (N,O,F).}$ $\text{2. Molecules has a lone pair of electrons on a small highly electronegative atom (N, O, F)}$ $\text{STEP 2:}$ $\text{Hydrogen bonding occurs in alcohols (CH}_3\text{CH}_2\text{OH}\text{), carboxylic acids (CH}_3\text{COOH}\text{), and amides (CH}_3\text{CONH}_2\text{) because they have hydrogen atoms directly attached to highly electronegative atoms like oxygen or nitrogen.}$ $\text{STEP 3:}$ $\text{Although the aldehydes and ketones are highly polar molecules, they don't have any hydrogen atoms attached directly to the oxygen, and so they can't hydrogen bond with each other. Therefore, acetone (CH}_3\text{COCH}_3\text{) does not exhibit hydrogen bonding.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}