Import Question JSON

Current Question (ID: 8124)

Question:

$\text{V versus T curves at constant pressure P}_1 \text{ and P}_2 \text{ for an ideal gas are as shown in the figure. The correct statement is-}$

Options:

1. $\text{P}_1 > \text{P}_2$
2. $\text{P}_1 < \text{P}_2$
3. $\text{P}_1 = \text{P}_2$
4. $\text{All of the above}$

Solution:

$\text{Hint: P} \propto \frac{1}{\text{V}}$ \n\n $\text{Explanation:}$ \n\n $\text{According to the Ideal gas equation; PV = nRT}$ \n\n $\text{So, V = nRT/P}$ \n\n $\text{Slope is inversely proportional to P . We can also see that slope nR/P}_1 > \text{nR/P}_2 \text{ or the value of P}_1 < \text{P}_2\text{.}$ \n\n $\text{Thus, option 2 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}