Import Question JSON

Current Question (ID: 8140)

Question:

$\text{At constant temperature, } 200\text{ cm}^3 \text{ of N}_2 \text{ at } 720\text{ mm and } 400\text{ cm}^3 \text{ of O}_2 \text{ at } 750\text{ mm pressure are put together in a one-litre flask. The final pressure of the mixture is-}$

Options:

1. $111\text{ mm}$
2. $222\text{ mm}$
3. $333\text{ mm}$
4. $444\text{ mm}$

Solution:

$\text{Hint: Use Boyle's Law} \text{Step 1:} \text{Boyle's Law states that the pressure (P) of a given quantity of gas varies inversely with its volume (V) at constant temperature.} \text{The formula is as follows:} \text{P}_1\text{V}_1 + \text{P}_2\text{V}_2 = \text{PV} \text{Step 2:} \text{Calculate the value of final pressure of the mixture as follows:} 720 \times 200 + 750 \times 400 = \text{P} \times 1000 = 444\text{ mm}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}