Import Question JSON

Current Question (ID: 8157)

Question:

The volume of 2.8 g of carbon monoxide at 27$^\circ$C and 0.821 atm pressure is: \n\n($\text{R} = 0.0821 \text{ L atm K}^{-1} \text{mol}^{-1}$)

Options:

1. $0.3 \text{ L}$
2. $1.5 \text{ L}$
3. $3 \text{ L}$
4. $30 \text{ L}$

Solution:

Hint: Use ideal gas equation\n\nStep 1:\nCalculate the moles of gas as follows:\nNumber of moles $= \frac{\text{mass}}{\text{molar mass}}$\n$\text{n} = \frac{2.8 \text{ g}}{28 \text{ g/mol}} = 0.1 \text{ mol}$\n\nStep 2:\nCalculate the volume of gas as follows:\n$\text{PV} = \text{nRT}$\n$\text{V} = \frac{\text{nRT}}{\text{P}} = \frac{0.1 \times 0.0821 \times 300}{0.821} = 3 \text{ L}$\n\n(Note: Temperature converted to Kelvin: 27$^\circ$C = 300 K)

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}