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Current Question (ID: 8184)

Question:
$\text{The partial pressure of oxygen in a flask containing 16 g } \text{O}_2 \text{ and 32 g } \text{SO}_2 \text{ is-}$
Options:
  • 1. $1/16 \text{ of total pressure}$
  • 2. $1/2 \text{ of total pressure}$
  • 3. $2/3 \text{ of total pressure}$
  • 4. $\text{None of the above}$
Solution:
$\text{Hint: } \text{P} = \text{P}_\text{T}\text{X}_{\text{gas}}$\n\n$\text{Explanation:}$\n\n$\text{Step 1:}$\n\n$\text{Calculate the number of moles is as follows:}$\n\n$\text{Number of moles of } \text{O}_2 = \frac{16}{32} = 0.5 \text{ mole}$\n\n$\text{Number of a mole of } \text{SO}_2 = \frac{32}{64} = 0.5 \text{ mole}$\n\n$\text{Step 2:}$\n\n$\text{Calculate the partial pressure of } \text{O}_2 \text{ as follows:}$\n\n$\text{P} = \text{P}_\text{T}\text{X}_{\text{gas}}$\n\n$\text{The partial pressure of } \text{O}_2 = \frac{0.5}{1.0} \times \text{total pressure}$\n\n$= \frac{1}{2} \text{ of total pressure}$\n\n$\text{Hence, the partial pressure of oxygen is 1/2 of total pressure.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}