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Current Question (ID: 8200)

Question:
In van der Waal's equation of state for a non-ideal gas, the term that accounts for the intermolecular force is-
Options:
  • 1. $V-b$
  • 2. $(P+a/V^2)$
  • 3. $RT$
  • 4. $(RT)^{-1}$
Solution:
Hint: $\left(P + \frac{a}{V^2}\right)(V - b) = RT$\n\nExplanation:\n\nThere are no intermolecular forces of attraction between molecules in ideal gas. But in case of real gas either attractive or repulsive forces are present between the particles. The $\frac{a}{V^2}$ terms define the intermolecular forces.\n\nHence, option two is the correct answer.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}