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Current Question (ID: 8219)

Question:
\text{Gases possess characteristic critical temperature which depends upon the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases:} \text{H}_2\text{: 33.2 K} \text{He: 5.3 K} \text{O}_2\text{: 154.3 K} \text{N}_2\text{: 126 K} \text{From the above data, the order of liquefaction of the given gases is-} \text{(write the order from the gas liquefying first)}
Options:
  • 1. $\text{H}_2, \text{He}, \text{O}_2, \text{N}_2$
  • 2. $\text{He}, \text{O}_2, \text{H}_2, \text{N}_2$
  • 3. $\text{N}_2, \text{O}_2, \text{He}, \text{H}_2$
  • 4. $\text{O}_2, \text{N}_2, \text{H}_2, \text{He}$
Solution:
$\text{Hint: Ease of liquefaction} \propto \text{Critical Temperature.}$ $\text{Tc} = 8a/27\text{Rb}$ $\text{The higher the critical temperature more easily is the gas liquified. Hence, the order of liquefaction starting with the gas liquefying first will be } \text{O}_2, \text{N}_2, \text{H}_2, \text{He}.$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}