Import Question JSON

Current Question (ID: 8251)

Question:

$\text{Which of the following is not a state function?}$

Options:

1. $\Delta S$
2. $\Delta G$
3. $\Delta H$
4. $\Delta Q$

Solution:

$\textbf{Hint:} \text{State functions do not depend on the path taken.}$\n\n$\text{State functions are the values that depend on the state of the substance like temperature, pressure or the amount or type of the substance, etc. H, E, S, G, P, T and V are the state function}$\n\n$\Delta Q \text{ is not a state function.}$\n\n$\text{Let us analyze each option:}$\n\n$\bullet \, \Delta S \text{ (change in entropy): This is a state function because entropy S is a state function, and the change between two states depends only on initial and final states.}$\n\n$\bullet \, \Delta G \text{ (change in Gibbs free energy): This is a state function because Gibbs free energy G is a state function.}$\n\n$\bullet \, \Delta H \text{ (change in enthalpy): This is a state function because enthalpy H is a state function.}$\n\n$\bullet \, \Delta Q \text{ (change in heat): This is NOT a state function because heat Q is a path function that depends on the process path taken, not just the initial and final states.}$\n\n$\text{State functions depend only on the current state of the system, while path functions (like heat and work) depend on how the process is carried out.}$\n\n$\text{Therefore, option (4) is correct.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}