Import Question JSON

Current Question (ID: 8253)

Question:
$\text{Which among the following state functions is an extensive property of the system?}$
Options:
  • 1. $\text{Temperature}$
  • 2. $\text{Volume}$
  • 3. $\text{Refractive index}$
  • 4. $\text{Viscosity}$
Solution:
\textbf{Hint: Temperature is a state function.} \textbf{Explanation:} \text{Examples of extensive properties include:} - \text{amount of substance, n} - \text{energy, E} - \text{enthalpy, H} - \text{entropy, S} - \text{Gibbs energy, G} - \text{heat capacity, } C_p - \text{Helmholtz energy, A or F} - \text{internal energy, U} - \text{Volume, V} \text{Intensive properties include temperature, T; refractive index, n; density, } \rho \text{; and viscosity, } \eta \text{.} \text{Let us analyze each option:} - \text{Temperature: This is an intensive property - it does not depend on the amount of substance present.} - \text{Volume: This is an extensive property - it depends on the amount of substance. If you double the amount of substance, the volume doubles.} - \text{Refractive index: This is an intensive property - it is characteristic of the material and does not depend on amount.} - \text{Viscosity: This is an intensive property - it is a characteristic of the material independent of amount.} \text{Extensive properties depend on the amount or size of the system, while intensive properties depend only on the nature of the substance.} \text{Thus, option 2 is the correct answer.}

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}