Import Question JSON

Current Question (ID: 8254)

Question:

$\text{Plants and living beings are examples of:}$

Options:

1. $\text{Isolated system}$
2. $\text{Adiabatic system}$
3. $\text{Open system}$
4. $\text{Closed system}$

Solution:

$\textbf{Hint:} \text{Exchange of both matter and energy takes place in an open system}$\n\n$\textbf{Explanation:} \text{The type of system is as follows:}$\n\n$\textbf{Step 1:} \text{Open system = Mass and energy both can be exchanged}$\n\n$\textbf{Step 2:} \text{Closed system = Mass can not be exchanged but energy exchange}$\n\n$\text{Isolated = Neither mass nor energy can be exchanged}$\n\n$\text{All plants and living beings are an example of an open system because it can exchange energy and mass with the surrounding.}$\n\n$\text{Let us understand why plants and living beings are open systems:}$\n\n$\bullet \, \textbf{Matter exchange:} \text{Plants take in } \text{CO}_2 \text{ from air and release } \text{O}_2\text{. Animals breathe in } \text{O}_2 \text{ and exhale } \text{CO}_2\text{. They consume food and excrete waste.}$\n\n$\bullet \, \textbf{Energy exchange:} \text{Plants absorb solar energy for photosynthesis and release heat. Animals take in chemical energy from food and release heat energy to surroundings.}$\n\n$\text{Since both matter and energy are freely exchanged with the environment, plants and living beings are perfect examples of open systems.}$\n\n$\text{Therefore, option (3) is correct.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}