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Current Question (ID: 8258)

Question:
$\text{Assume each reaction is carried out in an open container. For which of the following reactions will } \Delta H \text{ be equal to } \Delta U?$
Options:
  • 1. $\text{PCl}_5(\text{g}) \rightarrow \text{PCl}_3(\text{g}) + \text{Cl}_2(\text{g})$
  • 2. $2\text{CO}(\text{g}) + \text{O}_2(\text{g}) \rightarrow 2\text{CO}_2(\text{g})$
  • 3. $\text{H}_2(\text{g}) + \text{Br}_2(\text{g}) \rightarrow 2\text{HBr}(\text{g})$
  • 4. $\text{C}(\text{s}) + 2\text{H}_2\text{O}(\text{g}) \rightarrow 2\text{H}_2(\text{g}) + \text{CO}_2(\text{g})$
Solution:
\textbf{Hint:} \text{Change in number of moles of gases should be Zero} \Delta H = \Delta U + \Delta n_g RT \Delta n = 0 \Delta H = \Delta U \Delta n_g = \sum \text{Gaseous P} - \sum \text{Gas R} \text{Let us calculate } \Delta n_g \text{ for each reaction:} \textbf{1. } \text{PCl}_5(\text{g}) \to \text{PCl}_3(\text{g}) + \text{Cl}_2(\text{g}) \Delta n_g = (1 + 1) - 1 = +1 \textbf{2. } 2\text{CO}(\text{g}) + \text{O}_2(\text{g}) \to 2\text{CO}_2(\text{g}) \Delta n_g = 2 - (2 + 1) = -1 \textbf{3. } \text{H}_2(\text{g}) + \text{Br}_2(\text{g}) \to 2\text{HBr}(\text{g}) \Delta n_g = 2 - (1 + 1) = 0 \textbf{4. } \text{C}(\text{s}) + 2\text{H}_2\text{O}(\text{g}) \to 2\text{H}_2(\text{g}) + \text{CO}_2(\text{g}) \Delta n_g = (2 + 1) - 2 = +1 \text{For } \Delta H = \Delta U, \text{ we need } \Delta n_g = 0 \text{Only reaction 3 has } \Delta n_g = 0, \text{ therefore only for this reaction } \Delta H = \Delta U. \text{The relationship between enthalpy and internal energy is:} \Delta H = \Delta U + \Delta n_g RT \text{When } \Delta n_g = 0 \text{ (no change in number of gaseous moles), the } \Delta n_g RT \text{ term becomes zero, making } \Delta H = \Delta U. \text{Therefore, option (3) is correct.}

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}