Import Question JSON

Current Question (ID: 8259)

Question:

$\text{Combustion of glucose takes place according to the equation,}\n\n\text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{CO}_2 + 6\text{H}_2\text{O}, \Delta H = -72 \text{ K cal}\n\n\text{Energy required for the production of 1.6 g of glucose is -}\n\n\text{(Molecular mass of glucose = 180 g)}$

Options:

1. $0.064 \text{ kcal}$
2. $0.64 \text{ kcal}$
3. $6.4 \text{ kcal}$
4. $64 \text{ kcal}$

Solution:

$\text{Hint: Question is based on mole concept and unitary method}\n\n\text{From the reaction, it is clear that 1 mole or 180 g of glucose needs 72 kcal}\n\n\text{for 1 g of glucose, the energy required = }\frac{72}{180}\text{ kcal}\n\n\Delta H \text{ for 1.6 g} = \frac{72 \times 1.6}{180} = 0.64 \text{ kcal.}\n\n\text{Hence, option 2 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}