Import Question JSON

Current Question (ID: 8265)

Question:

$\text{Which plot represents an exothermic reaction?}$

Options:

1. $\text{A graph with enthalpy (H) on y-axis and time on x-axis, showing a downward arrow from point R (reactants) at higher enthalpy to point P (products) at lower enthalpy.}$
2. $\text{A graph with enthalpy (H) on y-axis and time on x-axis, showing an upward arrow from point R (reactants) at lower enthalpy to point P (products) at higher enthalpy.}$
3. $\text{A graph with enthalpy (H) on y-axis and time on x-axis, showing a horizontal line from R that curves upward into an energy barrier and then back down to P at the same enthalpy level as R.}$
4. $\text{A graph with enthalpy (H) on y-axis and time on x-axis, showing a horizontal line from R that curves downward into a valley and then back up to P at the same enthalpy level as R.}$

Solution:

$\text{Hint: Enthalpy decreases with time}$ $\text{In exothermic reaction, energy is released. Hence, enthalpy of system decreases with time. Hence, first option is the correct option.}$ $\text{In the first option, the graph shows enthalpy decreasing from reactants (R) to products (P), which correctly represents an exothermic reaction where energy is released to the surroundings.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}