Import Question JSON

Current Question (ID: 8266)

Question:

\text{Consider the following diagram for a reaction A} \rightarrow \text{C:} \text{[Energy diagram showing reactant A at a higher enthalpy level (}H_r\text{) and product C at a lower enthalpy level (}H_p\text{), with an arrow pointing downward from A to C along the reaction coordinate axis]} \text{The nature of the reaction is-}

Options:

1. $\text{Exothermic}$
2. $\text{Endothermic}$
3. $\text{Reaction at equilibrium}$
4. $\text{None of the above}$

Solution:

$\text{The reaction A } \rightarrow \text{ C is exothermic in nature because the total enthalpy of the product is less than the total enthalpy of the reactant.}$ $\text{The H}_\text{p} < \text{H}_\text{r}\text{. Hence,}$ $\Delta\text{H}_{\text{reaction}} = \text{H}_\text{p} - \text{H}_\text{r}$ $\Delta\text{H}_{\text{reaction}} = \text{ - ve}$ $\text{Since the enthalpy change is negative (}\Delta\text{H < 0), heat is released to the surroundings during the reaction, which is characteristic of an exothermic reaction. The diagram clearly shows the products at a lower energy level than the reactants, confirming that energy is released.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}