Solution:
$\text{Hint: A reversible process (infinitely slow) does the maximum work.}$
$\text{Step 1: Understand the nature of reversible and irreversible processes}$
$\text{A reversible process is one that proceeds infinitesimally slowly through a continuous series of equilibrium states.}$
$\text{An irreversible process occurs at a finite rate and involves non-equilibrium states.}$
$\text{Step 2: Analyze work in expansion processes}$
$\text{For an expansion process (where the gas increases in volume), the gas does work on the surroundings.}$
$\text{By thermodynamic convention, work done by the system is negative.}$
$\text{For an isothermal expansion of an ideal gas:}$
$\text{• In a reversible process, the work done is: } W_{\text{rev}} = -nRT\ln\frac{V_2}{V_1}$
$\text{• In an irreversible process, the work done is typically: } W_{\text{irr}} = -P_{\text{ext}}(V_2 - V_1)$
$\text{Where } P_{\text{ext}} \text{ is the constant external pressure.}$
$\text{Step 3: Compare reversible and irreversible work}$
$\text{For the same initial and final states in an isothermal expansion:}$
$\text{• A reversible process extracts the maximum possible work from the system}$
$\text{• An irreversible process extracts less work due to entropy generation within the system}$
$\text{This means that for expansion processes (where work is negative):}$
$|W_{\text{rev}}| > |W_{\text{irr}}|$
$\text{Since both values are negative, and the reversible process has a larger magnitude:}$
$W_{\text{rev}} < W_{\text{irr}}$
$\text{However, in terms of the absolute amount of work extracted from the system (ignoring the sign convention):}$
$|W_{\text{rev}}| > |W_{\text{irr}}|$
$\text{Step 4: Consider the physical meaning}$
$\text{The reason a reversible process yields more work (in magnitude) is that:}$
$\text{• In an irreversible process, some energy is lost to entropy generation}$
$\text{• This entropy must be transferred to the surroundings as heat, reducing the amount of energy available to do work}$
$\text{• A reversible process has no entropy generation, maximizing the work output}$
$\text{For expansion, where the work is negative, a more negative value of } W_{\text{rev}} \text{ means more work is done by the system.}$
$\text{Therefore, for the isothermal expansion of an ideal gas:}$
$W_{\text{rev}} < W_{\text{irr}} \text{ (in terms of signed values)}$
$\text{This means more work is extracted in a reversible process.}$
$\text{In terms of the absolute magnitude of work (ignoring signs):}$
$|W_{\text{rev}}| > |W_{\text{irr}}|$
$\text{Looking at the options, } W_{\text{rev}} > W_{\text{irr}} \text{ is correct in terms of comparing the absolute amount of work done, since more work is extracted in a reversible process.}$
$\text{Option 3 is the correct answer.}$