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Current Question (ID: 8297)

Question:
$\text{Consider the following graph.}$ $[\text{P-V diagram showing expansion from volume } V_i \text{ to } V_f \text{ with decreasing pressure curve}]$ $\text{The work done shown by the above-mentioned graph is-}$
Options:
  • 1. $\text{Positive}$
  • 2. $\text{Negative}$
  • 3. $\text{Zero}$
  • 4. $\text{Cannot be determined}$
Solution:
$\text{Hint: } W = -P\Delta V$ $\text{Step 1: Analyze the P-V diagram}$ $\text{Looking at the P-V diagram, we can observe that:}$ $\text{• The process starts at volume } V_i \text{ and ends at volume } V_f$ $\text{• The volume increases during the process } (V_i < V_f)$ $\text{• The pressure decreases as the volume increases}$ $\text{• The process follows a curved path, which appears to be a reversible expansion}$ $\text{Step 2: Determine the type of process and the work}$ $\text{This is an expansion process, as the volume increases from } V_i \text{ to } V_f$. $\text{In thermodynamics, work is calculated as the area under the curve in a P-V diagram:}$ $W = \int_{V_i}^{V_f} P \, dV$ $\text{The area under the curve in the given P-V diagram represents the work done during the process.}$ $\text{Step 3: Apply the sign convention}$ $\text{According to the thermodynamic sign convention:}$ $\text{• Work done BY the system on the surroundings is negative}$ $\text{• Work done ON the system by the surroundings is positive}$ $\text{Since this is an expansion process } (V_i < V_f) \text{, the system is doing work on the surroundings.}$ $\text{We can also use the simplified formula: } W = -P\Delta V$ $\text{Since } \Delta V = V_f - V_i > 0 \text{ for expansion, and with the negative sign in the formula, the work is negative.}$ $\text{The negative sign in the formula represents the convention that work done by the system is negative.}$ $\text{Step 4: Verify the conclusion}$ $\text{The area under the P-V curve represents the work done by the system during expansion.}$ $\text{According to thermodynamic conventions, this work is negative.}$ $\text{Therefore, the work done as shown by the graph is negative.}$

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{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}