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Current Question (ID: 8305)

Question:
$\Delta\text{H}^0_\text{f} (298\text{K}) \text{ of methanol is given by the chemical equation:}$
Options:
  • 1. $\text{C(diamond)} + \frac{1}{2}\text{O}_{2(g)} + 2\text{H}_{2(g)} \rightarrow \text{CH}_3\text{OH}_{(l)}$
  • 2. $\text{CH}_{4(g)} + \frac{1}{2}\text{O}_{2(g)} \rightarrow \text{CH}_3\text{OH}_{(g)}$
  • 3. $\text{CO}_{(g)} + 2\text{H}_{2(g)} \rightarrow \text{CH}_3\text{OH}_{(l)}$
  • 4. $\text{C(graphite)} + \frac{1}{2}\text{O}_{2(g)} + 2\text{H}_{2(g)} \rightarrow \text{CH}_3\text{OH}_{(l)}$
Solution:
$\text{Hint: Formation of one mole of a compound from its elements in their most stable states of aggregation (also known as reference states) is called Standard Molar Enthalpy of Formation.}$ $\text{Heat of formation is defined as the heat exchange when one mole of a compound is formed from its constituent elements at STP. In case of allotropes, most stable allotrope is taken into account. Among graphite and diamond graphite is stable. Hence, heat of formation of CH$_3$OH is represented by the eqn.}$ $\text{C(graphite)} + \frac{1}{2}\text{O}_{2(g)} + 2\text{H}_{2(g)} \rightarrow \text{CH}_3\text{OH}_{(l)}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}