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Current Question (ID: 8325)

Question:
$\text{The unit of entropy is -}$
Options:
  • 1. $\text{J mol}^{-1}$
  • 2. $\text{JK mol}^{-1}$
  • 3. $\text{J mol}^{-1} \text{K}^{-1}$
  • 4. $\text{J}^{-1} \text{K}^{-1} \text{mol}^{-1}$
Solution:
$\text{Hint: Use the concept of the 2nd law of thermodynamics}$ $\text{Step 1: Understand what entropy is and how it's defined}$ $\text{Entropy (S) is a thermodynamic property that measures the degree of disorder or randomness in a system. It is related to the second law of thermodynamics, which states that the entropy of an isolated system always increases over time.}$ $\text{Step 2: Examine the mathematical definition of entropy}$ $\text{According to the second law of thermodynamics, for a reversible process, the change in entropy (}\Delta\text{S) is defined as:}$ $\Delta\text{S} = \frac{q_{\text{rev}}}{\text{T}}$ $\text{where:}$ $q_{\text{rev}} = \text{heat transferred in a reversible process (J)}$ $\text{T} = \text{temperature (K)}$ $\text{Step 3: Determine the unit of entropy based on this definition}$ $\text{From the equation above, we can derive the unit of entropy:}$ $\text{Unit of } \Delta\text{S} = \frac{\text{Unit of heat}}{\text{Unit of temperature}} = \frac{\text{Joule (J)}}{\text{Kelvin (K)}}$ $\text{For molar entropy, we include mol}^{-1} \text{ in the unit:}$ $\text{Unit of molar entropy} = \text{J K}^{-1} \text{mol}^{-1} \text{ or } \text{J mol}^{-1} \text{K}^{-1}$ $\text{The correct representation is J mol}^{-1} \text{K}^{-1}\text{, which indicates joules per mole per kelvin.}$ $\text{Therefore, the unit of entropy is J mol}^{-1} \text{K}^{-1}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}