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Current Question (ID: 8335)

Question:
$\text{Which of the following thermodynamic quantities is an outcome of the second law of thermodynamics?}$
Options:
  • 1. $\text{Work}$
  • 2. $\text{Enthalpy}$
  • 3. $\text{Internal energy}$
  • 4. $\text{Entropy}$
Solution:
$\text{Hint: Second law of thermodynamics tells about randomness and disorderness}$ $\text{The second law of thermodynamics is fundamentally concerned with entropy, which is a measure of disorder or randomness in a system. Key points about the second law include:}$ $\text{1. It establishes that a machine with 100\% efficiency cannot be created.}$ $\text{2. In any energy conversion process, there is always some waste of energy: Total energy = useful work + waste of energy}$ $\text{3. The entropy of an isolated system always increases over time.}$ $\text{For comparison, the other laws of thermodynamics address different concepts:}$ $\text{- 1st law of thermodynamics deals with work, internal energy, and enthalpy. It establishes the principle of conservation of energy.}$ $\text{- 3rd law of thermodynamics states that a perfect crystal at absolute zero would have zero entropy, though perfect crystals do not exist in reality.}$ $\text{Among the given options:}$ $\text{- Work is associated with the 1st law}$ $\text{- Enthalpy is associated with the 1st law}$ $\text{- Internal energy is associated with the 1st law}$ $\text{- Entropy is directly associated with the 2nd law}$ $\text{Therefore, entropy (option 4) is the thermodynamic quantity that is an outcome of the second law of thermodynamics.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}