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Current Question (ID: 8338)

Question:
$\text{Change in entropy is negative for:}$
Options:
  • 1. $\text{Bromine (l)}\rightarrow\text{Bromine(g)}$
  • 2. $\text{C(s) + H}_2\text{O(g)} \rightarrow\text{CO(g) + H}_2\text{(g)}$
  • 3. $\text{N}_2\text{(g,10 atm)}\rightarrow\text{N}_2\text{(g,1 atm)}$
  • 4. $\text{Fe (1mol, 400 K)} \rightarrow \text{Fe(1mol, 300 K)}$
Solution:
$\text{Hint: Temperature increases, entropy also increases.}$ $\text{To determine which process has a negative entropy change, we need to analyze each option based on principles of entropy:}$ $\text{1. Bromine (l)}\rightarrow\text{Bromine(g):}$ $\text{This represents a phase change from liquid to gas. The gaseous phase has more disorder and freedom of movement than the liquid phase. Therefore,}$ $\Delta\text{S is positive for this process.}$ $\text{2. C(s) + H}_2\text{O(g)} \rightarrow\text{CO(g) + H}_2\text{(g):}$ $\text{Here we have 1 solid and 1 gas molecule converting to 2 gas molecules. Since gases have higher entropy than solids, and we end up with more gas molecules, the disorder increases. Therefore,}$ $\Delta\text{S is positive for this reaction.}$ $\text{3. N}_2\text{(g,10 atm)}\rightarrow\text{N}_2\text{(g,1 atm):}$ $\text{This represents a decrease in pressure for a gas. When pressure decreases, gas molecules have more available space and greater freedom of movement, which increases disorder. Therefore,}$ $\Delta\text{S is positive for this process.}$ $\text{4. Fe (1mol, 400 K)} \rightarrow \text{Fe(1mol, 300 K):}$ $\text{This represents a decrease in temperature of iron from 400 K to 300 K. When temperature decreases, molecular motion decreases, leading to less disorder in the system. Therefore,}$ $\Delta\text{S is negative for this process.}$ $\text{Based on the analysis, only option 4 shows a negative entropy change, as a decrease in temperature leads to decreased molecular motion and disorder.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}