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Current Question (ID: 8339)

Question:
$\text{The occurrence of a reaction is impossible if:}$
Options:
  • 1. $\Delta\text{H is +ve ; }\Delta\text{S is also + ve but }\Delta\text{H < T}\Delta\text{S}$
  • 2. $\Delta\text{H is - ve ; }\Delta\text{S is also - ve but }\Delta\text{H > T}\Delta\text{S}$
  • 3. $\Delta\text{H is - ve ; }\Delta\text{S is + ve}$
  • 4. $\Delta\text{H is + ve ; }\Delta\text{S is - ve}$
Solution:
$\text{Hint: If }\Delta\text{G value is negative then reaction will occur}$ $\text{To determine when a reaction is impossible, we need to analyze the Gibbs free energy equation:}$ $\Delta\text{G} = \Delta\text{H} - \text{T}\Delta\text{S}$ $\text{For a reaction to be spontaneous (possible), }\Delta\text{G must be negative.}$ $\text{For a reaction to be non-spontaneous (impossible), }\Delta\text{G must be positive.}$ $\text{Let's analyze each option:}$ $\text{Option 1: }\Delta\text{H is +ve ; }\Delta\text{S is also + ve but }\Delta\text{H < T}\Delta\text{S}$ $\text{If }\Delta\text{H < T}\Delta\text{S}\text{, then }\Delta\text{G} = \Delta\text{H} - \text{T}\Delta\text{S} < 0$ $\text{This means the reaction is spontaneous and possible, not impossible.}$ $\text{Option 2: }\Delta\text{H is - ve ; }\Delta\text{S is also - ve but }\Delta\text{H > T}\Delta\text{S}$ $\text{If }\Delta\text{H > T}\Delta\text{S}\text{, then }\Delta\text{G} = \Delta\text{H} - \text{T}\Delta\text{S} < 0$ $\text{(Note: When }\Delta\text{S is negative, -T}\Delta\text{S becomes positive, so we need }\Delta\text{H to be more negative than T}\Delta\text{S is positive)}$ $\text{This means the reaction is spontaneous and possible, not impossible.}$ $\text{Option 3: }\Delta\text{H is - ve ; }\Delta\text{S is + ve}$ $\text{In this case, both terms in }\Delta\text{G} = \Delta\text{H} - \text{T}\Delta\text{S}\text{ are negative, making }\Delta\text{G}\text{ always negative.}$ $\text{This means the reaction is always spontaneous and possible at all temperatures, not impossible.}$ $\text{Option 4: }\Delta\text{H is + ve ; }\Delta\text{S is - ve}$ $\text{In this case, both terms in }\Delta\text{G} = \Delta\text{H} - \text{T}\Delta\text{S}\text{ are positive, making }\Delta\text{G}\text{ always positive.}$ $\text{This means the reaction is always non-spontaneous and impossible at all temperatures.}$ $\text{Therefore, option 4 is the correct answer. When }\Delta\text{H is positive and }\Delta\text{S is negative, the reaction is impossible at all temperatures.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}